59

I need to serialize / deserialize a datetime into yyyyMMdd format for an XML file. Is there an attribute / workaround I can use for this?

1
  • You can manipulate the getter and setter of the variable. For example I had an enum Sex{Unknown, Female, Male} and I had a string setter which formattet m into male and f into female. The xml serializer also wrote f and m inseatd of the full enum name. Worked fine but there's nearly no practical usage for this.
    – BlueWizard
    Aug 9, 2015 at 16:01

2 Answers 2

71

No, there isn't. If it's in that format, then it's not a valid dateTime as far as XML Schema is concerned.

The best you can do is as follows:

[XmlIgnore]
public DateTime DoNotSerialize {get;set;}

public string ProxyDateTime {
    get {return DoNotSerialize.ToString("yyyyMMdd");}
    set {DoNotSerialize = DateTime.Parse(value);}
}
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  • 13
    Worth noting: both a get/set must be present. I spent a half hour debugging why my property wasn't being serialized. It turns out I had no 'set', because I thought to myself, 'I'll never be changing this value; why bother writing a set?'
    – spamguy
    Feb 7, 2014 at 17:47
  • 1
    @spamguy: XmlSerializer only handles public properties with both a public get and public set. Feb 7, 2014 at 18:26
22

XmlElementAttribute#DataType should provide what you need:

[XmlElement(DataType="date")]    
public DateTime Date1 {get;set;}

This will get Date1 property serialized to the proper xml date format.

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  • 3
    No, the problem is that I needed to serialize it to a non-standard xml date format. The accepted solution is what I went for.
    – cjk
    Feb 17, 2011 at 11:13
  • 1
    This doesn't work for me, gives a build error. [XmlElement(DataType="date")] works. Jul 17, 2013 at 9:07
  • Thanks. Fixed my problem. I was trying to remove the Time component. Cheers! Apr 1, 2014 at 6:44
  • Works great if you need YYYY-MM-DD, which I actually need DD/MM/YYYY, Doh! Jul 15, 2020 at 6:31

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