How to skip the space in the txt file

Question

I'm trying to count all the letters from a text but I want to exclude the counting of a letter next to a space

from collections import Counter

text = 'in the seas and let fowl multiply in the earth \nand the evening and the mo were the fifth day \nand gd slet the earth bring forth the livngke man in our image after our likeness and let d over all the'
txt = [x for x in text if x not in '\n'] #this what i did for excluding the newline 

cc = Counter(zip(text, text[1:])).items() 
print(cc)

I want to remove all the pair with space - like this (('n', ' '), 4)

From this

dict_items([(('i', 'n'), 5), (('n', ' '), 4), ((' ', 't'), 8), (('t', 'h'), 12), (('h', 'e'), 8), (('e', ' '), 10), ((' ', 's'), 2), (('s', 'e'), 1), (('e', 'a'), 3), (('a', 's'), 1), (('s', ' '), 2), ((' ', 'a'), 5), (('a', 'n'), 6), (('n', 'd'), 5), (('d', ' '), 7), ((' ', 'l'), 4), (('l', 'e'), 3), .....)

to this

dict_items([(('i', 'n'), 5), (('t', 'h'), 12), (('h', 'e'), 8), (('s', 'e'), 1), (('e', 'a'), 3), (('a', 's'), 1), (('a', 'n'), 6), (('n', 'd'), 5), (('l', 'e'), 3), .....)

Answer 1

The number of non-whitespace characters in a string:

import re

text = 'in the seas and let fowl multiply in the earth \nand the evening and the mo were the fifth day \nand gd slet the earth bring forth the livngke man in our image after our likeness and let d over all the'

no_space = re.sub('\s', '', text)
print(len(no_space))

Result:

156

If you need those pairs for something else:

pairs = list(zip(no_space, no_space[1:]))
print(pairs)

Result:

[('i', 'n'), ('n', 't'), ('t', 'h'), ('h', 'e'), ('e', 's'), ('s', 'e'), ...]

I'm using re because this covers all whitespace by removing everything that matches \s (including newlines, tabs, spaces, etc.). If you don't want to use re for some reason, and are only interested in ignoring regular spaces and newlines:

no_space = ''.join(c for c in text if c not in ' \n')